y=2[x-(4-x)]-3(x+1)

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Solution for y=2[x-(4-x)]-3(x+1) equation: 


Simplifying
y = 2[x + -1(4 + -1x)] + -3(x + 1)
y = 2[x + (4 * -1 + -1x * -1)] + -3(x + 1)
y = 2[x + (-4 + 1x)] + -3(x + 1)

Reorder the terms:
y = 2[-4 + x + 1x] + -3(x + 1)

Combine like terms: x + 1x = 2x
y = 2[-4 + 2x] + -3(x + 1)
y = [-4 * 2 + 2x * 2] + -3(x + 1)
y = [-8 + 4x] + -3(x + 1)

Reorder the terms:
y = -8 + 4x + -3(1 + x)
y = -8 + 4x + (1 * -3 + x * -3)
y = -8 + 4x + (-3 + -3x)

Reorder the terms:
y = -8 + -3 + 4x + -3x

Combine like terms: -8 + -3 = -11
y = -11 + 4x + -3x

Combine like terms: 4x + -3x = 1x
y = -11 + 1x

Solving
y = -11 + 1x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -11 + 1x

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